Vapour pressure of benzene is 200 mm of Hg. When 2 gram of a non-volatile solute dissolved in 78 gram benzene, benzene has vapour pressure of 195 mm of Hg. Calculate the molar mass of the solute. [Molar mass of benzene is 78 g/`mol^(-1)`]

The boiling point of benzene is 353.23 K . When 1.80 g of a non-volatile solute was dissolved in 90 g benzene, the boiling point is raised to 354.11 K . Calculate the molar mass of the solute. ( K_(b) for benzene is 2.53 K kg mol^(-1) )

The boiling point of benzene is 353.23 K when 1.80 g of a non-volatile, non-ionising solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of solute. " " [Given K_(b) for benzene = 2.53 K kg mol^(-1) ]

The vapour pressure of pure benzene is 639.7 mm Hg and the vapour pressure of solution of a solute in benzene at the temperature is 631.9 mm Hg . Calculate the molality of the solution.

On dissolving 2.34g of non-electrolyte solute in 40g of benzene, the boiling point of solution was higher than benzene by 0.81K. Kb value for benzene is 2.53 K kgmol^(-1) .Calculate the molar mass of solute. [Molar mass of benzene is 78 gmol^(-1) ]

The vapour pressure of acetone at 20^(@)C is 185 torr. When 1.2 g of a non-volatile substance was dissolved in 100 g of acetone at 20^(@)C , its vapour pressure was 183 torr. The molar mass ( " g mol"^(-1)) of the substance is :

(a) The boiling point of benzene is 353.23K. When 1.80g of a non-volatile,non-ionisable solute was dissolved in 90g benzene, the boiling point raised to 354.11K. Calculate molarass of the solute.[Kb for benzene =2.53K kg mol-1]. (b)Define :(i) molality of a solution. (ii) Isotonic solutions.

Aqueous solution of 3% non-volatile solute exerts a pressure of 1 bar at the boiling point of the solvent. Calculate the molar mass of solute.