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DeltaH^(0) for a reaction F(2) + 2HCl ra...

`DeltaH^(0)` for a reaction `F_(2) + 2HCl rarr 2HF + Cl_(2)` is given as `-352.8 kJ. Delta H_(f)^(0)` for HF is `-268.3 KJ mol^(-1)`, then `Delta H_(f)^(0)` of HCl would be

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`DeltaH= H_(P)-H_(R) =2H_(HF)-2H_(HCl)= -352.8KJ=2(-268.3)-2(H_(HCl))`
`2(H_(HCl))=-536.6 +352.8 =-183.8KJ` (or)`H_(HCl)=-91.9KJ mol^(-1)`
The standard heat of formation of `HCl=-91.9KJ mol^(-1)`.
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