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Latent heat of fusion of ice is 6 kJ mol...

Latent heat of fusion of ice is `6 kJ mol^(-1)`. Calculate the entropy change in the fusion of ice. 

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Change in entropy, `DeltaS=q_(rev)/T`
`q_(rev)` =Latent heat of fusion = `6KJmol^(-1)=6000Jmol^(-1)`
`T` = Freezing point of water = `273K`
`DeltaS=600/273=21.98JK^(-1)mol^(-1)`(or)`DeltaS=6000/(273xx18)=1.22Jk^(-1)g^(-)`
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