The vapour pressures of benzene at 303k and 333k are respectively 1.53`xx10^(4) and 5.2xx10^(4)Nm^(-2)` Calculate the latent heat of evaporation of benzene over this temperature.

Explanation

Loge `P_(2)/P_(1)=(DeltaHv)/(2.30R)[(T_(2)-T_(1))/(T_(1)T_(2))]`,where `DeltaHv`is latent heat of evportation.
`2.303"log" "(5.2xx10^(4))/(1.52xx10^(4))=(DeltaHv)/8.314[(333-303)/(333xx303)]`
`DeltaH_(v)=34215J=34.215KJ`