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Zn((s))+Fe(aq)^(2+) Leftrightarrow Zn(aq...

`Zn_((s))+Fe_(aq)^(2+) Leftrightarrow Zn_(aq)^(2+) +Fe_((s)`. The vale of `K_(c)`for this reaction is `10^(23). Calculate the standard free energy change.

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Change in standard free energy,`DeltaG^(@)=-2.303RTlog_(10)10^(23) Cal" "Mol^(-1)`
`triangleG^(@)=-2.303 xx 1.987 xx 298 x log_(10) 10^(23)"cal mol"^(-1)`
Standard free energy for the reaction is -13.57 kcal mol`""^(-1)`.
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