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The equilibrium constant of a reaction i...

The equilibrium constant of a reaction is 73. Calculate standard free energy change.

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Equilibrium constant Kis related to `DeltaG^(@)" as "DeltaG^(@)=-2.303R" T" log " K`
substituting the values, `K=73,T=298K" and "R=8.314JK^(-1)mol^(-1)`
`DeltaG^(@)=-2.303xx8.314xx298xxlog_(10)^(73)J mol^(-1)`
standard free energy change = `-10.632KJmol^(-1)`.
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