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Covert 10^(@)C into Fahrenheit scale....

Covert `10^(@)`C into Fahrenheit scale.

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C `= 10^(@)` C.
`(C)/(5) = (F -32)/(9) " " F = (9)/(5) C+ 32 = (9)/(5) (-10) + 32 `
18 + 32 = `14^(@)F. " " 10^(@) C = 14^(@)`Fm
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