If I is moment of inertia of a disc about an axis passing through its centre then find change in moment of inertia due to small change in its temperature `Deltat` (`alpha` is coefficient of linear expansion).

Explanation

Let I ` = (MR^(2))/(2) " then " Delta I = (M)/(2) 2R Delta R `
`(Delta I)/(I) = (MR Delta R )/(MR^(2)//2) = 2 (Delta R)/(R)`
But `(Delta R)/(R) = alpha Delta t rArr (Delta I )/(I) = 2 alpha Delta T and Delta I = 2I alpha Delta t.`