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'M' kg of water 't' ""^(@)C is divided i...

'M' kg of water 't' `""^(@)`C is divided into two parts so that one part of mass 'm' kg when converted into ice at `0^(@)`C would release enough heat to vapourise the other part, then `(m)/(M)` is equal to
[ Specific heat of water = 1 cal `g^(-1) ""^(@) C^(-1)` latent heat of fussion of ice = 80 cal `g^(-1)` , Latent heat of steam = 540 cal `g^(-1)` ]

A

640 - t

B

`(720 - t)/(640)`

C

`(640 + t)/(720)`

D

`(640 - t)/(720)`

Text Solution

Verified by Experts

The correct Answer is:
D
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