A rectangular block has dimensions 5 cm `xx ` 5 cm `xx 10 cm ` . Calculate the resistance measured between (a) two square ends and (b) the opposite rectanglar ends specific resistance of the material is `3.5xx10^(-5)` `Omega` m

Explanation

a) Resistance between two square ends `R_1 = (rhol)/(A)`
`R_1 = (3.5xx10^(-5) xx 10xx10^(-2))/(5xx5xx10^(-4)) = 1.4xx10^(-3) Omega`

b) Resistance between the opposite rectangular ends
`R_2 = (rhol)/(A)`
`R_2 = (3.5xx10^(-5) xx 5xx10^(-2))/(5xx10xx10^(-4)) = 3.5 xx 10^(-4) Omega`