The temperature coefficient of resistance of a wire is `0.00125^@ C^(-1)` w.r.t temperature at 300 K at which the resistance of the wire is one ohm. Find the temperature at which the resistance of the wire will be 2 ohm.

Explanation

`alpha = 0.00125^@ C, t_1 = 300 K,R_1 =1 Omega`
`R_2 = 2Omega, t_2=?`
Temperature coefficient resistance
`alpha =(R_2 -R_1)/(R_ (t_2 -t_1)) , 0.00125 = (2-1)/(1(t_2 - 300))`
`t_2-300 =1/(0.00125)`
`t_2 =300 +(10^3)/(1.25) = 300 + 800 = 1100 K`
Final temperature `t_2 = 1100 K`