Find potential difference between points A and B of the network shown in Fig. and distribution of given main current through different resistors.

Explanation

Between points A and B resistors of `4 Omega, 6 Omega and 8 Omega` resistances are in series and these are in parallel to `9 Omega` resistor .
Equivalent resistance of series combination is
`R_1 = (4 + 6 + 8) ` ohm `= 18 Omega`
Equivalent resistance between A and B is
`R = 9 xx 18//(9 +18) `ohm = `6 Omega`
Potential difference between A and B is
`V= IR = 2.7 xx 6V = 16.2 V`
Current through `9 Omega ` resistor `= 16.2//9 =1.8 A`
Current through `4 Omega , 6 Omega and 8 Omega ` resistors = `2.7 -1.8 =0.9 A`