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Find the BE/A from the following data, m...

Find the BE/A from the following data, mass of `""_(3)Li^(7)= 7.01653 ` amu, mass of proton = 1.00759 amu mass of neutron = 1.00898 amu

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The correct Answer is:
5.6 MeV
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Calculate the binding energy per nucleon of ""_(17)^(35)Cl urcleus. Given that mass of ""_(17)^(35)Cl nucleus = 34.98000 u, mass of proton = 1.007825 u, mass of neutron = 1.008665 u and I u is equivalent to 931 Mev.

How much energy is required to separate the typical middle mass nucleus ._(50)^(120)Sn into its constituent nucleons ? (Mass of ._(50)^(120)Sn=119.902199u , mass of proton = 1.007825u and mass of neutron = 1.008665u)

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  • How much energy is required to separate the typical middle mass nucleus ""_(50)^(120)Sn into its constituent nucleons. (Mass of ""_(50)^(120)Sn = 119.902199 u , mass of proten = 1.007825 u and mass of neutron = 1.008665 u)

    A
    1021 Mev
    B
    921 Mev
    C
    1121 Mev
    D
    821 Mev

  • How much energy is required to separate the typical middle mass nucleus ._50^120Sn into its constituent nucleons. (Mass of ._50^120Sn = 119.902199 u , mass of proton = 1.007825 u and mass of neutron = 1.008665 u)

    A
    1021 Mev
    B
    921 Mev
    C
    1121 Mev
    D
    821 Mev

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    Explore conceptually related problems

    Calculate The binding energy per nucleon of ._(6)^(12)C nucleus. Nuclear mass of ._(6)^(12)C=12.000000 u , mass of proton = 1.007825 u and mass of neutron = 1.008665 u.

    Calculate the binding energy per nucleon of ._(20)^(40)Ca . Given that mass of ._(20)^(40)Ca nucleus = 39.962589 u, mass of a proton = 1.007825 u,, mass of Neutron = 1.008665 u and 1 u is equivalent to 931 MeV.

    Calculate the binding energy per nucleon of ._(17)^(35)Cl nucleus. Given that mass of ._(17)^(35)Cl nucleus = 34.98000 u, mass of proton = 1.007825u, mass of neutron = 1.008665u and 1 is equivalent to 931 MeV.

    Calculate the binding energy per nucleon of ._17^35Cl nucleus. Given that mass of ._17^35Cl nucleus = 34.98000 u, mass of proton = 1.007825 u, mass of neutron = 1.008665 u and 1 u is equivalent to 931 Mev.

    Calculate the (i) mass defect, (ii) binding energy and (iii) the binding energy per nucleon of ""_(6)^(12)C nucleus. Nuclear mass of ""_(6)^12C = 12. 000000 u, mass of proton=1.007825 u and mass of neutron=1.008665 u.

    Calculate the binding energy per nucleon of ._20^40Ca . Given that mass of ._20^40Ca nucleus = 20 39.962589 u. mass of a proton = 1.007825 u , mass of neutron = 1.008665 u and luis equivalent to 931 Mev.

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