Assuming the splitting of `U^(235)` nucleus liberates 200 MeV energy, find (a) the energy liberated in the fission of 1 kg of `U^(235)` and (b) the mass of the coal with calorific value of 30 kJ/g which is equivalent to 1 kg of `U^(235)`

Answer

(a) `8.09 xx10^(13)J` (b) `2.7xx10^(6) kg`