Home
Class 12
MATHS
Find the equation of the cirlcle which c...

Find the equation of the cirlcle which cuts orthogonally the three circles `x^(2)+y^(2)+2x+4y+1=0,2(x^(2)+y^(2))+6x+8y-3=0` and `x^(2)+y^(2)-2x+6y-3=0`

Text Solution

Verified by Experts

The correct Answer is:
0
Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of the circle which cuts orthogonally the three circles x^(2) + y^(2) + 4x + 2y + 1 = 0 , 2x^(2) + 2y^(2) + 8x + 6y - 3 = 0 , x^(2) + y^(2) + 6x - 2y - 3 = 0 is

The equation of the circle which cuts orthogonally the three circles x^2+y^2+4x+2y+1=0, 2x^2+2y^2+8x+6y-3=0, x^2+y^2+6x-2y-3=0 is

The equation of the circle which cuts orthogonally the three circles, x^2+y^2+2x+17y+4=0, x^2+y^2+7x+6y+11=0, x^2+y^2-x+22y+3=0 is

Find the equations of the circles which cut orthogonally the circles x^2+y^2-6y+1=0, x^2+y^2-4y+1=0 and touch the line 3x+4y+5=0

The equation of the circle which passes the origin and cuts orthogonally each of the circles x^(2) + y^(2) - 6x + 8 = 0 " and " x^(2) + y^(2) - 2x - 2y = 7 is