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if the two circles x^2 + y^2 + 2gx + ...

if the two circles
` x^2 + y^2 + 2gx + 2fy = 0 and `
`x^2 + y^2 + 2g'x + 2 f'y = 0 `touch each other then show that f'g = fg'

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The correct Answer is:
`g'f`
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