A thin circular ring of mass Mand radius r is rotating about its axis with a constant angular velocity `omega`. Four objects each of mass m, are kept gently to the opposite ends of two perpendicular diameters of the ring. The angular velocity of the ring will be

Options

A. `(Momega)/(4m)`
B. `(Momega)/(M+4m)`
C. `((M+4m)omega)/M`
D. `((M-4m)omega)/(M+4m)`

Answer

B

Explanation

According to conservation of angular momentum,
`L=Iomega`= constant. Therefore, `I_(2)omega_(2) = I_(1)omega_(1)`
or `omega_(2)=(I_(1)omega_(1))/(I_(2))=(Mk^(2)omega)/((M+4m)k^(2))=(Momega)/(M+4m)`