The moment of inertia of a uniform circular disc of radius R and mass M about an axis passing from the edge of the disc and normal to the disc is

Options

A. `MR^(2)`
B. `1/2MR^(2)`
C. `3/2MR^(2)`
D. `7/2MR^(2)`

Answer

C

Explanation

M.I. of disc about its normal `=1/2MR^(2)`
M.I. about its one edge =`MR^(2)+(MR^(2))/2`
(Perpendicular to the plane)
Moment of inertia =`3/2MR^(2)`.