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The period of revolution of planet A aro...

The period of revolution of planet A around the sun is 8 times that of B. The distance of A from the sun is how many times greater than that of B from the sun ?

A

4

B

5

C

2

D

3

Text Solution

Verified by Experts

The correct Answer is:
A
Period of revolution of planet `A(T_(A))=8T_(B)`.
According to Kepler.s 111 law of planetary motion `T^(2) prop r^(3)`.
Therefore `((r_(A))/(r_(B)))^(3)=((T_(A))/(T_(B))^(2))=((8T_(B))/(T_(B))^(2))=64`
or `(r_(A))/(r_(B))=4" or " r_(A)=4r_(B)`
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Knowledge Check

  • The period of revolution of planet A round from the sun is 8 times that of B. The distance of A from the sun is how many times greater then tht of B from the sun ?

    A
    5
    B
    4
    C
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    D
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    A
    `2`
    B
    `3`
    C
    `4`
    D
    `5`

  • The period of revolution of a planet around the sun is 8 times that of the earth. If the mean distance of that planet from the sun is r, then mean distance of earth from the sun is

    A
    `r//2`
    B
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    C
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    D
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