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The acceleration due to gravity near the...

The acceleration due to gravity near the surface of a planet of radius R and density d is proportional to

A

`d//R^(2)`

B

`dR^(2)`

C

dR

D

`d//R`

Text Solution

Verified by Experts

The correct Answer is:
C
`g=(GM)/(R^(2))=G("volume"xx"density")/(R^(2))`
`=G.(4)/(3)(piR^(3).d)/(R^(2))=(4 piG)/(3).d.R" or "g prop dR`
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