Home
Class 12
PHYSICS
A satellite of mass m revolves around th...

A satellite of mass m revolves around the earth of radius R at a height x from its surface. If g is the acceleration due to gravity on the surface of the earth, the orbital speed of the satellite is

A

gx

B

`(gR)/(R-x)`

C

`(gR^(2))/(R+x)`

D

`((gR^(2))/(R+x))^(1//2)`

Text Solution

Verified by Experts

The correct Answer is:
D
Gravitational force=centripetal force
`:. (GMm)/((R+x)^(2))=(mv_(0)^(2))/((R+x)) rArr (GM)/((R+x))=v_(0)^(2)`
`rArr v_(0)^(2)=(GM)/((R+x))=(R^(2)g)/((R+x)) rArr v_(0)=[(gR^(2))/((R+x))]^(1//2)`
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    MTG-WBJEE|Exercise WB JEE WORKOUT CATEGORY 3 : One or More than One Option Correct Type|10 Videos

  • GRAVITATION

    MTG-WBJEE|Exercise WB JEE Previous Years Questions (CATEGORY 1: Single Option Correct Type|7 Videos

  • GRAVITATION

    MTG-WBJEE|Exercise WB JEE Previous Years Questions (CATEGORY 1: Single Option Correct Type|7 Videos

  • ELECTROSTATICS

    MTG-WBJEE|Exercise (WB JEE Previous Years Questions ) CATEGORY 3 : One or More than One Opion correct Type|4 Videos

  • HEAT AND THERMAL PHYSICS

    MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS|15 Videos

Similar Questions

Explore conceptually related problems

A satellite of mass m revolves around the earth of radius R at a hight x from its surface. If g is the acceleration due to gravity on the surface of the earth, the orbital speed of the satellite is

The satellite is moving round the earth (radius of earth = R) at a distance r from the centre of the earth. If g is the acceleration due to gravity on the surface of the earth. The acceleration of the satellite will be

A satellite is in a circular orbit round the earth at an altitude R above the earth's surface, where R is the radius of the earth. If g is the acceleration due to gravity on the surface of the earth, the speed of the satellite is

An earth satellite of mass m revolves in a circular orbit at a height h from the surface of the earth. R is the radius of the earth and g is acceleration due to gravity at the surface of the earth. The velocity of the satellite in the orbit is given by

The ratio of acceleration due to gravity at a height 3R above earth 's surface to the acceleration due to gravity on the surface of the earth is (where R=radius of earth)

If R is the radius of the earth , the height from its surface at which the acceleration due to gravity is 9% of its value at the surface is

A satellite is revolving around the earth in a circular orbit at an altitude h where the acceleration due to gravity is g'. If the earth is a sphere of radius R then the period of the satellite is give by

The ratio of acceleration due to gravity at a height 3 R above earth's surface to the acceleration due to gravity on the surface of earth is (R = radius of earth)

A body of mass m rises to a height h=R/5 from the surface of earth. If g is the acceleration due to gravity at the surface of earth, the increase in potential energy is (R = radius of earth)