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The displacement of a particle in S.H.M....

The displacement of a particle in S.H.M. varies according to the relation`x = 4(cos pi t + sin pit)` . The amplitude of the particle is

A

`-4`

B

4

C

`4sqrt(2)`

D

8

Text Solution

Verified by Experts

The correct Answer is:
C
`x = 4(cos pi t+ sin pit)`
`= 4sqrt(2) (1/sqrt(2) cos pit + 1/sqrt(2) sin pit)`
`=4sqrt(2) [sin pi/4 cos pi t + cos pi/4 sin pit]`
`=4sqrt(2) [sin pit cos pi/4 + cos pi t sin pi/4]`
`=4sqrt(2) sin (pi t + pi/4)`
Hence, the amplitude of particle is `4sqrt(2)`.
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