The current I in the circuit shown is

Options

A. `1.33A`
B. zero
C. `2.00 A`
D. `1.00 A`

Answer

A

Explanation

Given circult can be redrawn as shown in figure

here first two cells are in parallel so net emf
`epsi_(eq) = ( sum epsi/r 2/1 + 2/2 )/(sum 1/r 1/1 +1/2) =2V`
current in the circuit ,` I= (2 +2)/( 1+2) =4/3 =1.33 A `