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A charged particle (change q ) is moving...

A charged particle (change q ) is moving in a circle of radius R with uniform speed v. The associated magnetic moment `mu` is given by

A

`qvR^(2)`

B

`qvR^(2)//2`

C

qvR

D

`qvR^(2)//2`

Text Solution

Verified by Experts

The correct Answer is:
D
Magnetic moment `mu = IA`
Since `T = (2piR)/v`.Also, `I=q/T=(qv)/(2piR)`
`therefore mu=((qv)/(2piR))(piR^(2))=(qvR)/2`
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