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The angle of dip at place is delta. If d...

The angle of dip at place is `delta`. If dip is measured in a plane making an angle `theta` with the magnetic meridian, the apparent angle of dip `delta_(1)` will be equal to

A

`tan_(-1) (tan delta sec theta)`

B

`tan^(-1)(tan delta sin theta)`

C

`tan^(-1) (tan theta costheta)`

D

`tan^(-1) (tandelta cosec theta)`

Text Solution

Verified by Experts

The correct Answer is:
A
`tan delta = "vertical component"/"Horizontal component"=V/H`
Again, `tandelta_(1) = V/(H. cos theta) = (tandelta)/(cos that)=tan delta sec theta`
`implies delta_(1) = tan^(-1) (tantheta sec theta)`
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Knowledge Check

  • The angle of dip at a place is delta . If the dip is measured in a plane makinng an angle theta with the magnetic merdian, the apparent angle of dip delta_(1) will be

    A
    `Tan^(-1)(tandelta)`
    B
    `tan^(-1)(tan delta cos theta)`
    C
    `tan^(-1)(tan delta sec theta)`
    D
    `0`

  • The angle of dip is the angle

    A
    Between the vertical component of earth's magnetic field and magnetc meridian
    B
    Between the vertical component of earth's magnetic field and geographical meridian
    C
    Between the earth's magnetic field direction and horizontal direction
    D
    Between the magnetic meridian and the geographical meridian

  • The angle of dip at a place on the earth gives

    A
    The horizontal component of the earth's magnetic field
    B
    The location of the geographic meridian
    C
    The vertical component of the earth's field
    D
    The direction of the earth's magnetic field

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