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The angle of dip at place is delta. If d...

The angle of dip at place is `delta`. If dip is measured in a plane making an angle `theta` with the magnetic meridian, the apparent angle of dip `delta_(1)` will be equal to

A

`tan_(-1) (tan delta sec theta)`

B

`tan^(-1)(tan delta sin theta)`

C

`tan^(-1) (tan theta costheta)`

D

`tan^(-1) (tandelta cosec theta)`

Text Solution

Verified by Experts

The correct Answer is:
A
`tan delta = "vertical component"/"Horizontal component"=V/H`
Again, `tandelta_(1) = V/(H. cos theta) = (tandelta)/(cos that)=tan delta sec theta`
`implies delta_(1) = tan^(-1) (tantheta sec theta)`
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