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A bar magnet having a magnetic moment of...

A bar magnet having a magnetic moment of `2.0 xx 10^(-4) J//T` is free to rotate in a horizontal plane. A horizontal magnetic field `B = 5 xx 10^(-5) T` exists in the space. Then the work done in rotating the magnet slowls from a direction parallel to the field to a direction `60^(@)` from the field is

A

0.1 J

B

0.3 J

C

0.5 J

D

0.7 J

Text Solution

Verified by Experts

The correct Answer is:
C
The work done by the external agent = change in potential energy
`= (-MB costheta_(2)) - (-MBcostheta_(1))`
`=-M(cos60^(@)-cos0^(@))`
`=1/2MB = 1/2xx(2.0xx10^(4)J//T)(5xx10^(-5)T = 0.5J`
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