Electrolytic cell containing molten nickel chloride and aluminium chloride solutions are arranged in a series. If on passing same current through both the solution, if 18 gm Al is obtained then how much Ni is obtained ? (Atomic mass of Al=27 and Ni=58.5 gm `mol^(-1)`)

Options

A. 58.5 gm
B. 29.25 gm
C. 117 gm
D. 5.85 gm

Answer

A

Explanation

(i) Reaction when Al metal is formed :
`Al^(3+)+3e^(-) to Al_((S))`
So, 3 mol `e^(-) to 1` mol AI
So, 27 gm Al required 3 F current.
So for 18 gm Al, amount of electricity
`=(18xx3)/(27)=2F`
(ii) 2F current is also passed through `Ni^(2+)` solution as it is in series.
`Ni^(2+)+2e^(-) to NI_((S))`