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What is the reflection of the graph of t...

What is the reflection of the graph of the function y=sin x along the y=x.

Text Solution

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The correct Answer is:
The reflection of the graph of function y=sin x along the line y =x is the graph of the inverse function `y=sin^(-1)x`.
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Knowledge Check

  • Suppose f(x)=(x+1)^(2) for x ge -1 . If g(x) is a function whose graph is the reflection of the graph of f(x) in the line y=x , then g(x)=

    A
    `(1)/((x+1)^(2)),x gt -1`
    B
    `-sqrt(x)-1`
    C
    `sqrt(x)+1`
    D
    `sqrt(x)-1`

  • Suppose f(x)=(x+1)^(2) for xge-1 . If g(x) is the function whose graph is the reflection of the graph of f(x) in the line y = x, then g(x) =

    A
    `-sqrt(x)-1`
    B
    `sqrt(x)-1`
    C
    `(1)/((x-1)^(2)),xgt -1`
    D
    `sqrt(x)+1`

  • Suppose f(x)=(x+1)^(2) for xge-1 . If g(x) is the function whose graph is reflection of the graph of f(x) with respect to the line y=x , then g(x) equals :

    A
    `-sqrt(x)-1,xge0`
    B
    `(1)/((x+1)^(2)),xgt -1`
    C
    `sqrt(x+1),xge-1`
    D
    `sqrt(x)-1,xge0`

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    A function y = f(x) has a second order derivative f''(x) =6(x-1) . If its graph passes thro' the point (2, 1) and at the point the tangent to the graph is y=3x-5 , then the function is :

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