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The image of the point (1,6,3) in the li...

The image of the point (1,6,3) in the line `x/1=(y-1)/2=(z-2)/3` is

A

(1,0,7)

B

(7,0,1)

C

(2,7,0)

D

(-1,-6,-3)

Text Solution

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The correct Answer is:
A
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Find the image of the point (1,6,3) in the line (x)/(1) = (y-1)/(2)=(z-2)/(3) . Also write the equation of the line joining the given point and its image and find the length of the segment joining the given point and its image.

The image of the point (- 1, 3, 4) in the plane: x-2y=0 is:

Knowledge Check

  • The distance of the point (1,2,1) from the line (x-1)/2=(y-2)/1=(z-3)/2 is

    A
    a.`sqrt5/3`
    B
    b.`(2sqrt3)/5`
    C
    c.`20/3`
    D
    d.`(2sqrt5)/3`

  • The distance of the point (1, 2, 1) from the line (x-1)/(2) = (y-2)/(1)=(z-3)/(2) is

    A
    `(2sqrt3)/(5)`
    B
    `sqrt5/3`
    C
    `(2sqrt5)/(3)`
    D
    `(20)/3`

  • The distance of the point (3,8,2) from the line (x-1)/2 = (y-3)/4 = (z-2)/3 measured parallel to the plane 3x+2y-2z +15 = 0 is

    A
    2
    B
    3
    C
    6
    D
    7

    • Similar Questions

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    Assuming that straight lines work as the plane mirror for a point, find the image of the point (1, 2) in the line x - 3y + 4 = 0 .

    The distance of the point (1, 2, -4) from the line (x-3)/(2)=(y-3)/(3)=(z+5)/(6) is

    Find the coordinates of the point, where the line (x-2)/(3)=(y+1)/(4)=(z-2)/(2) intersects the plane x - y + z - 5 = 0 . Also find the angle between the line and the plane.

    The plane, which passes through the point (3, 2, 0) and the line (x-3)/1=(y-6)/5=(z-4)/4 is :

    Locus of the image of the point (2,3) in the line (2x-3y+4)+k(x-2y+3)=0, k in R is a

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