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If ((1-i)/(1+i))^(96)=a+ib, then (a,b) i...

If `((1-i)/(1+i))^(96)=a+ib`, then (a,b) is

A

(1,1)

B

(1,0)

C

(0,1)

D

(0,-1)

Text Solution

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The correct Answer is:
B
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