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If veca=hati + 2 hatj + 2hatk, |vecb|=5 ...

If `veca=hati + 2 hatj + 2hatk, |vecb|=5` and angle between `veca and vecb` is `(pi)/(60,` then the area of the triangle formed by these two vectors as two side is :

A

`(15 sqrt3)/(2)`

B

`(15)/(4)`

C

15

D

`(15)/(2)`

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The correct Answer is:
B
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