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A transistor is having a beta equal to 8...

A transistor is having a `beta` equal to 80 has a change in base current of `250 mu A`. Calculate the change in the collector current.

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`beta=80, Delta I_(B) = 250 mu A = 250 xx 10^(-6)A`
We have, `beta= (Delta l_C)/(Delta I_(B))`
`Delta I_C = beta xx Delta Ι_B`
`= 80xx250xx10^(-6)`
`= 20,000 xx 10^(-6)`
`Delta I_C = 20mA`
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