In a parallel plate capacitor with air between the plates, each has an area `8xx10^(-3)m^(2)` and distance between the plates is 2 mm. Calculate the capacitance of the capacitor. If this capacitor is connected to a 50 V supply, what is the charge on each plate of the capacitor? (Absolute permittivity of free space `=8.85xx10^(-12)Fm^(-1))`

Explanation

Given :
`A= 8xx10^(-3) m^(2),d=2 mm =2xx10^(-3) m, V = 50 V, epsilon_(0)= 8.85xx10^(-12) Fm^(-1)`
Capacitance of parallel plate capacitor is
`C= (epsilon_(0)A)/(d)`
` C = (8.85xx10^(-12)xx8xx10^(-3))/(2xx10^(-3))`
` C = 35.4xx10^(-12)` F
C= 35.4 pF
Charge the each capacitor plate is
q = CV = `35.4xx10^(-12)xx50`
`q= 1.770xx10^(-12)`
`q = 1.770xx10^(-9)`
q=1.770 n C