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In young's double slit experiment distan...

In young's double slit experiment distance between the slits is 0.5 mm. When the screen is kept at a distance of 100 cm from the slits, the distance of ninth bright fring from the centre of the fringe system is 8.835 mm. Find the wavelength of light used.

Text Solution

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Given :
`x_(n) = 8.85xx10^(-3)` d = 0.5 mm= `0.5xx10^(-3)` m, D=1m , n =9
Distance of `n^(th)` bright fringe is given by
`x_(n) =(nlambdaD)/(d)`
`lambda=(x_(n)d)/(nD)=(8.835xx10^(-3)xx0.5xx10^(-3))/(9xx1) = (4.4175)/(9) xx10^(-6)m = 4908 Å`
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