A `20 Omega` resistor, 1.5 H inductor and `35 mu H` capacitor are connected in series with a 220 V, 50 ac supply. Calculate the impedance of the circuit and also find the current through the circuit.

Explanation

`R = 20 Omega, L = 1.5 H, C = 35 xx 10^(-6)F, V = 220 V, v = 50 Hz, Z = ?, I = ?`
We have, impedance , `Z = sqrt(R^(2) + (X_(L) - X_(C))^(2))`
`X_(L) = omega L = 2pi vl = 2 xx 3.14 xx 50 xx 1.5`
`X_(L) = 471 Omega`
`X_(C) = (1)/(omega C) = (1)/(2pi v C) = (1)/(2 xx 3.14 xx 50 xx 1.5)`
`X_(C) = 90.99 Omega`
`Z = sqrt((20)^(2) + (471 - 90.99)^(2))`
`Z = 380.27 Omega`
`I = (V)/(Z) = (220)/(380.27) = 0.578 A`