In a parallel plate capacitor with air between the plates, each plate has an area of `6xx10^(-3)m^2` and the distance between the plates is 3 m. Calculate the capacitance of the capacitor. If this capacitor is connected to a 100V supply. What is the charge on the each plate of the capacitor?

Explanation

Here `A = 6xx10^(-3) m^(2) , d = 3xx10^(-3) , epsilon_(0) = 8.85 xx10^(-12) "Fm"^(-1) V = 100 V`
we have
`C = (epsilon_(0)A)/d`
`= (8.85xx10^(-12) xx6xx10^(-3))/(3xx10^(-3))`
`C = 17.7 xx10^(-12)F`
The charge on each plate is equal and opposite and the charge
`Q = CV`
`Q = 17.7 xx10^(-12) xx100`
`= 17.7 xx10^(-10)C`
`Q = 1.77 nC`