A stone is thrown vertically at a speed of `30 ms^(-1)` taking an angle of `45^(@)` with the horizontal. What is the maximum height reached by the stone ? Take `g = 10 ms^(-2)`.

Options

A. 30 m
B. 22.5 m
C. 15 m
D. 10 m

Answer

B

Explanation

`H_("max") = (v^(2) sin^(2) theta)/(2g)`
`H_("max") = (30^(2) sin^(2)(45))/(2 xx 10)`
`H_("max") = 22.5 m`