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What is a period of revolution of earth ...

What is a period of revolution of earth satellite ? Ignore the height of satellite above the surface of earth.
Given :
The value of gravitational acceleration `g= 10 m s^(-2)`
Radius of earta `R_(E)= 6400 km`. Take `pi=3.14`.

A

85 minutes

B

156 minutes

C

83.73 minutes

D

90 minutes

Text Solution

Verified by Experts

The correct Answer is:
C
`T = 2pisqrt((R)/(g)) = 2pisqrt((6400 xx 10^(3))/(10))`
`T = 5024 s = 83.73` min
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