What is the value of shunt resistance required to convert a galvanometer of resistance `100 Omega` into an ammeter of range 1 A ?
Given: Full scale deflection of the galvanometer is 5 mA.

Options

A. `(5)/(9.95) Omega`
B. `(9.95)/(5) Omega`
C. `0.5 Omega`
D. `0.05 Omega`

Answer

A

Explanation

`S = (I_(g)G)/(I-I_(g)) = (5 xx 10^(-3) xx 10^(2))/(1-5 xx 10^(-3)) = (0.5)/(1-5 xx 10^(-3)) = (5)/(10-0.05) = (5)/(9.95) Omega`