A body of mass 50 kg is suspended using aspring balance inside a lift at rest. If the lift starts falling freely, the reading of the spring balance is

Options

A. `= 50 kg`
B. `gt 50 kg`
C. `lt 50 kg`
D. `=0`

Answer

D

Explanation

Given,
Mass of the body, m = 50 kg
When lift is moving dowbn,
Scale reading `= (m(g-a))/(g)`
If lift starts falling freely, then a = g
Now, scale reading `= (m(g-g))/(g)=0`