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The mass defect of ""(2)^(4)He is 0.03 ...

The mass defect of `""_(2)^(4)He` is 0.03 u. The binding energy per nucleon of helium (in MeV) is

A

`27.93`

B

`6.9825`

C

`2.793`

D

`69.825`

Text Solution

Verified by Experts

The correct Answer is:
B
Mass defect of `""_(2)^(4)He = 0.03 u`
Mass number = 4
Building energy `= 0.03xx9.31=27.93`
Binding energy per nucleon `= (27.93)/(4)=6.9825`
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