The frequency of an alternating current is 50 Hz. What is the minimum time taken by current to reach its peak value from rms value ?

Options

A. `0.02s`
B. `5 xx 10^(-3) S `
C. `10 xx 10^(-3) S `
D. `2.5 xx 10^(-3) S`

Answer

D

Explanation

`i=i_0 sin omega t`
` at = (pi)/(4) ,t_1 =(1)/( 8 f)`
Att `=t_2 , I =i_0 ,implies t_2 (1)/(4f)`
` Delta t=t_2 -t_1 = 2.5 ms`