A certain charge 2Q is divided at first into two parts `q_(1)` and `q_(2)`. Later the charges are placed at a certain distance. If the force of interaction between two charges is maximum then `Q/(q_(1))` = ________.

Options

A. 1
B. 4
C. `0.5`
D. 2

Answer

A

Explanation

`q_1 +q_2 = 2Q`
`F alpha q_1 q_2`
` alpha q_1 (2 Q -q_1)`
` F alpha 2q_1 Q-q_(1)^2`
`(dF)/(dq_1) =0implies 2Q-2q_1 =0 therefore q_1 =Q`
`(q_1)/(Q)=1`