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The trajectory of a projectile projected...

The trajectory of a projectile projected from origin is given by the equation `y = x - (2x^(2))/(5)` .The initial velocity of the projectile is

A

`25 ms^(-1)`

B

`2 //5 ms^(-1)`

C

`5 //2ms^(-1)`

D

`5 ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D

`y= ax - bx ^2 , as a=I= tan theta implies theta = 45^@ `
` b=2/5 =(g)/(2v^2 cos^2 theta)`
` U^2 = (5 g)/( 4 cos ^2 theta)`
` U^2 = ( 5g )/( 4 cos 45^@ ) = (5g)/(2) = 2.5 g = 25 m//s`
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