A hydrogen atom in ground state absorbs 10.2 eV of energy. The orbital angular momentum of the electron is increased by

Options

A. `3.16 xx 10 ^(-34 ) Js`
B. `1.05 xx 10^(-14) Js `
C. `4.22 xx 10^(-34) Js`
D. `2.11 xx 10^(-34 ) Js`

Answer

B

Explanation

`L= (nh)/(2 pi)`
`epsi_0 -epsi_1 = Delta epsi ,As Delta = 10.2 eV & E_1 =- 13.6 eV`
`epsi_2 =- 3.4 eV Vimplies n=2`
`Delta L=L_2 -L_1 = 1.05 xx 10 ^(-34) Js`