An inductor of inductance L and resistor R are joined together in series and connected by a source of frequency `omega`. The power dissipated in the circuit is

Options

A. `(V)/(R^2 + omega^2 L^2)`
B. `(R^2 + omega^2 L^2)/( V)`
C. `(V^2 R)/( sqrt(R^2 +omega^2L^2))`
D. `(V^2 R)/( R^2 + omega^2 L^2)`

Answer

C

Explanation

Rl circuit
` P=V _(" rms") I_("rms") cos phi, cos phi = (R )/( Z ) = V (V )/(Z ), (R )/(Z) = (V^2 R)/(sqrt(R^2 = ( Omega L)^2)))`