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3A t0 2B ,rate of reaction + (d[B])/(dt)...

`3A t0 2B` ,rate of reaction `+ (d[B])/(dt)`is equal to

A

`-3/2 (d[A])/(dt)`

B

`-2/3 (d[A])/(dt)`

C

`+2 (d[A])/(dt)`

D

`-1/3 (d[A])/(dt)`

Text Solution

Verified by Experts

The correct Answer is:
B
`- 1/3 (d[A])/(dt)=+ 1/2 (d[B])/(dt)`
`- 2/3 (d[A])/(dt) =+ (d[B])/(dt)`
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