The number of oxygen atoms in 4.4 gm of `CO_2` is,

Options

A. `1.2xx10^(23)`
B. `6xx10^(22)`
C. `6xx10^(23)`
D. `12xx 10^(23)`

Answer

A

Explanation

44 g of `CO_2` contain `=6.023 xx 10^(23)` molecules of `CO_2`
`4.4 g` of `CO_2` will contain `=(6.023xx10^(23))/(44) xx 4.4 = 6.023 xx 10^(22)` molecules of `CO_2`
1 molecule of `CO_2` contain two oxygen atoms.
`6.023xx10^(22)` molecules of `CO_2` will contain `2xx 6.023xx10^(22) = 1.2xx10^(23)` oxygen atoms.