In the reaction, `Fe(OH)_(3(g)) hArr Fe_((aq))^3+ +3OH_((aq))^-` if the concentration of `OH^-` ions is decreased by 1/4 times, then the equilibrium concentration of F`e^(3+)` will increase by,

Options

A. 8 times
B. 16 times
C. 64 times
D. 4 times

Answer

C

Explanation

`K_C = [x] [3x]^3`
When concentration of `OH^-` ions is decreased by `1/4` times `K_C = [x^1] [(3x)/(4)]^3`
Equation eq. (i) and (ii)
`x xx (3x)^3 = x^1 ((3x)/(4))^3`
`64x =x^1`