By passing electric current,`NaClO_3`, is converted into `NaClO_4`, according to the following equation:
`NaClO_3 + H_2O rarr NaClO_4 + H_2`
How many moles of `NaClO_4`,, will be formed when three Faradays of charge ispassed through `NaCIO_3`?

Options

A. 0.75
B. 1
C. 1.5
D. 3

Answer

C

Explanation

`{:(NaClO_((3)) + H_2O rarr NaClO_(4) + H_2),(" "(+5)" "(+7)):}`
2F charges required for give 2 moles of electrons therefore 3F of charge give = 3/2 = 1.5 moles of electrons,
Henc, 1.5 mole of `NaClO_4` will be formed .